I performed the Palo Alto Speedometer test whereby you count the number of revolutions of the speedometer cable in 52 ft 9 1/2 inches. Instead of driving or pushing my car this distance I calculated the circumference of the tire (79.48 inches), tires are 205/70/14 and determine I would need to make 7.97 revolutions of the tire to travel the 52 ft 9 1/2 inches. With one side of the car jacked up I turned the tire and came to 6.0 revolutions of the speedometer cable. Does this sound right? Palo Alto seem to think the number should be about 12.
Input is appreciated.
(Posted this yesterday, but for some reason it didn't appear on the site)
When you turn only one wheel, the driveshaft rotates only half as many times as when you rotate both (because of the differential). So your 6 rotations of the speedometer cable would have been 12 if you had rotated both wheels.
BUT -- while your computation of 797 tire revolutions per mile (7.97 for a hundredth of a mile) is theoretically accurate, in practice the tire rotates a few more times per mile because the weight of the car flattens it slightly on the bottom. For example, for a few 205/70/14 tires I selected at random, the Tire Rack gives 821, 819, and 822 revolutions per mile (respectively 8.21, 8.19, and 8.22 per hundredth of a mile). The number is slightly different for different tire makes, and of course changes a bit with wear. If your speedometer cable rotates 12 times in a hundredth of a mile with 7.97 tire revolutions for that distance, it would rotate about 12.4 times with 8.22 tire revolutions for that distance. This would seem enough of a difference to affect speedometer calibration, so you might think about actually pushing the car the hundredth of a mile suggested by Palo Alto to get a more accurate result for your particular tires.
Chris